Divine proportion of the Great Pyramid

Figure 1

          The height of the 36th course from the natural rock base (35th course  from the pavement (H) = 1162.602377 inches high from the base of the ground's solid rock.   Divine proportion (the number Phi) = 1.618033988    

 

        ● 1162.602377 x 1.618033988 = 1881.130161 inches = floor length line of the Grand Gallery.
        ● Height of the Great Pyramid = 5813.011885 inches 5813.011885 x 1.618033988  = 9405.650803 inches Length of the Grand Gallery = 1881.130161 inches 9405.650803  x 5 = 1881.130161 inches.    ● Length of the Pyramid's base side = 9131.05 inches  

 

9131.05 : 1.618033988 = 5643.299256 inches

5643.299256 : 3 = 1881.130161 inches   

 

        ● Length of the Pyramid's base side = 9131.05 inches

 

9131.05 x 1.618033988 = 14,774.34925 inches

 

14,774.34925 : 1881.13016 = 7.853975

 

7.853975 x 4 = 31.4159 = 10Pi    

 

        ● The Pyramid's passages' angle of ascent =  26.3026897º

        Sine 26.3026897º = 0.443113275

 

1881.130161 x 0.443113275 = 833.5537463 inches:

 

833.5537463 : 1.618033988 = 515.1645469

515.1645469 x 4  = 2060.658188  inches = ten width of the King's Chamber = distance from the Pyramid's base to the Boss (see " One inch of the eccentricity" p. 46-48).        

 

        ● The floor line of the Grand Gallery  is 1881.130161 inches.                

        Angle of rise of the Pyramid's casing-stone = 51.85399754°

        Tangent 51.85399754° = 1.273240621

1881.130161 : 1.273240621 = 1477.434925  inches

1477.434925 : 1.618033988 = 913.105 inches   

 

        ● The base length of the Great Pyramid = 9131.05  inches.

        Angle of the Grand Gallery = 26.3026897°

        Sine 26.3026897° = 0.443113275

 

913.105 x 0.443113275 = 404.608947 inches

 

404.608947 x 1.273240621 = 515.1645469 inches

 

515.1645469 : 2.5 = 206.0658189 inches = width of the King's Chamber     

 

        ● Length of the King's chamber =  412,131638 inches

       

        412.1316378 : 1.618033988 = 254.7113601 inches = circumference of the circle T (Figure 1).
Figure 48.

        d = 81.07721253 inches

 

Area of the Circle A = 5162.821769 squared inches = area of the square ABCDA = 71.85277844 inches

 

60 71.85277844 x 1.618033988 = 116.2602376 inches = length of the Antechamber.

 

116.2602376  x 1.618033988 = 188.113016 inches = 10th part of the length of the Grand Gallery.   

 

        ● The number 5 is the relationship between the proportion of the 36th(35th) course and the original height of the Great Pyramid:

 

1162.602377 x 5 = 5813.011885inches.   

 

        The architect of the Great Pyramid knew that Earth's equatorial diameter is 12,757.00336 km long, and he took 5th part of that length:

 

12,757.00336 : 5 = 2551.400672 km    

 

        How did the length of 2551.400672 km the architect incorporate in the dimension of the Grand Gallery? He did that very simple: with the knowledge of the correlation of a time and speed, and with the number Phi (1.618033988):

        In order to travel the distance of 2551.400672 km in one day (24 hours), a certain object would have to travel at a speed of 29.53010037 meters per second or 1162.602377 inches per second. And the number Phi is coming: 29.53010037 x 1.618039988 = 47.78070607 meters = 1881.132016 inches = length of the Grand Gallery.   

 

        Who was familiar with the Earth's measurements and with the number Phi during that ancient time? The ancient Egyptians did not know of the length of the Earth's equatorial diameter, which means that they were not the builders of the Great Pyramid. Who has adjusted all these measurements?   

 

        ● The circumference of the Earth at the equator is 40,077.27418 km

 

61 40,077.27418 : 5 = 8015.45436 km

 

        In order to travel the distance of 8015.45436 km in one day (24 hours), a certain object would have to travel at a speed of  92.77146801 meters per second, or 3652.42 inches per second. 3652.42 x 1.618033988 = 5909.739699 inches

 

5909.739699 : 3.1419 = 1881.13016 inches = the length of the Grand Gallery.

 

Figure 2

● d = 1881.130161 inches = 47.78070609 m = length of the Grand Gallery Area of the circle T = 1793.059252 m² = area of the square BC = 42.34453037 m

 

42.34453037 : 1.618033988 = 26.17035902 m

        If a certain object was to travel with a speed of  26.17035902 m/sec, for one day it would travel a distance of 2261.119019 km 2261.119019 x 5 = 11,305.5951 km Square whose side is 11,305.5951 km long has the same surface area as a circle whose diameter is 12,757.00336 km =  equatorial diameter of the Earth.